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lib64
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python3.6
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site-packages
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zope
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interface
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..
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__init__.py
(3.33 KB)
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__pycache__
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_compat.py
(1.65 KB)
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_flatten.py
(1.03 KB)
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_zope_interface_coptimizations.cpython-36m-x86_64-linux-gnu.so
(32.54 KB)
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adapter.py
(22.87 KB)
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advice.py
(7.31 KB)
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common
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declarations.py
(30.85 KB)
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document.py
(3.89 KB)
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exceptions.py
(1.95 KB)
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interface.py
(20.02 KB)
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interfaces.py
(42.11 KB)
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registry.py
(22.74 KB)
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ro.py
(1.96 KB)
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verify.py
(4.78 KB)
Editing: ro.py
############################################################################## # # Copyright (c) 2003 Zope Foundation and Contributors. # All Rights Reserved. # # This software is subject to the provisions of the Zope Public License, # Version 2.1 (ZPL). A copy of the ZPL should accompany this distribution. # THIS SOFTWARE IS PROVIDED "AS IS" AND ANY AND ALL EXPRESS OR IMPLIED # WARRANTIES ARE DISCLAIMED, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED # WARRANTIES OF TITLE, MERCHANTABILITY, AGAINST INFRINGEMENT, AND FITNESS # FOR A PARTICULAR PURPOSE. # ############################################################################## """Compute a resolution order for an object and its bases """ __docformat__ = 'restructuredtext' def _mergeOrderings(orderings): """Merge multiple orderings so that within-ordering order is preserved Orderings are constrained in such a way that if an object appears in two or more orderings, then the suffix that begins with the object must be in both orderings. For example: >>> _mergeOrderings([ ... ['x', 'y', 'z'], ... ['q', 'z'], ... [1, 3, 5], ... ['z'] ... ]) ['x', 'y', 'q', 1, 3, 5, 'z'] """ seen = {} result = [] for ordering in reversed(orderings): for o in reversed(ordering): if o not in seen: seen[o] = 1 result.insert(0, o) return result def _flatten(ob): result = [ob] i = 0 for ob in iter(result): i += 1 # The recursive calls can be avoided by inserting the base classes # into the dynamically growing list directly after the currently # considered object; the iterator makes sure this will keep working # in the future, since it cannot rely on the length of the list # by definition. result[i:i] = ob.__bases__ return result def ro(object): """Compute a "resolution order" for an object """ return _mergeOrderings([_flatten(object)])
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